-2x^2+14x+6=0

Solution for -2x^2+14x+6=0 equation:

-2x^2+14x+6=0

a = -2; b = 14; c = +6;
Δ = b2-4ac
Δ = 142-4·(-2)·6
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{61}}{2*-2}=\frac{-14-2\sqrt{61}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{61}}{2*-2}=\frac{-14+2\sqrt{61}}{-4}
$